Evaluate the monomial division:
| countingwithgroupsof10 | |
| left |
Simplify monomial term number 1
countingwithgroupsof10
No simplification is needed
Simplify monomial term number 2
left
No simplification is needed
Our modified expression is:
| left) | |
Check to see if we can simplify constants:
No GCF exists, so we continue,
the constants stay the same in the numerator and denominator.
Simplify c:
We only have a c term in the numerator,
so we leave this where it is
Simplify e:
We only have a e term in the denominator,
so we leave this where it is
Simplify f:
We only have a f term in the numerator,
so we leave this where it is
Simplify f:
We only have a f term in the denominator,
so we leave this where it is
Simplify f10:
We only have a f10 term in the numerator,
so we leave this where it is
Simplify g:
We have the same g1 term in the numerator and denominator,
so they cancel each other out
Simplify h:
We only have a h term in the numerator,
so we leave this where it is
Simplify i:
We have the same i1 term in the numerator and denominator,
so they cancel each other out
Simplify l:
We only have a l term in the denominator,
so we leave this where it is
Simplify n:
We have the same n1 term in the numerator and denominator,
so they cancel each other out
Simplify o:
We have the same o1 term in the numerator and denominator,
so they cancel each other out
Simplify p:
We only have a p term in the numerator,
so we leave this where it is
Simplify r:
We only have a r term in the numerator,
so we leave this where it is
Simplify s:
We only have a s term in the numerator,
so we leave this where it is
Simplify t:
We have the same t1 term in the numerator and denominator,
so they cancel each other out
Simplify u:
We have the same u1 term in the numerator and denominator,
so they cancel each other out
Simplify w:
We only have a w term in the numerator,
so we leave this where it is
Build our final answer:
| countingwithgroupsof10 | |
| left |
| = |
| cff10hprsw |
| e1fl |
