Prove provesqrt(2)isirrational
Use proof by contradiction.
Assume √
2 is rational.
This means that √
2 = p/q for some integers p and q, with q <>0.
We assume p and q are in lowest terms.
Square both sides and we get:
2 = p
2/q
2Cross multiply:
p
2 = 2q
2This means p
2 must be an even number
This means p is also even since the square of an odd is odd.
So we have p = 2k for some integer k:
2q
2 = p
2 = (2k)
2 = 4k
22q
2 = 4k
2Divide each side by 2
q
2 = 2k
2q
2 is also even, therefore q must be even
Since the square of an odd number is odd.
So both p and q are even.
This contradicts are assumption that p and q were in lowest terms in p/q.
So √2 cannot be rational.
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- an inferential argument for a mathematical statement, showing that the stated assumptions logically guarantee the conclusion
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