Solve e
2q=48
Since we have e = 2.718281828459, a becomes 2.718281828459
We need to solve for q, therefore, in order to remove it from the power portion, we take the natural log of both sides
Ln(e
2q) = Ln(48)
There exists a logarithmic identity which states: Ln(a
n) = n * Ln(a)
Using that identity, we have n = 2q and a = e, so our equation becomes:
2qLn(e) = 3.8712010109079
Given that e = 2.718281828459, we have:
2q * Ln(2.718281828459)
(2 * 1)q = 3.8712010109079
2q = 3.8712010109079
Divide each side of the equation by 2
q =
1.9356005054539