Solve e2q=48

Since we have e = 2.718281828459, a becomes 2.718281828459
We need to solve for q, therefore, in order to remove it from the power portion, we take the natural log of both sides
Ln(e2q) = Ln(48)

There exists a logarithmic identity which states: Ln(an) = n * Ln(a)
Using that identity, we have n = 2q and a = e, so our equation becomes:
2qLn(e) = 3.8712010109079

Given that e = 2.718281828459, we have:

2q * Ln(2.718281828459)
(2 * 1)q = 3.8712010109079
2q = 3.8712010109079

Divide each side of the equation by 2

2q
2
=
  
3.8712010109079
2

q = 1.9356005054539