Evaluate the monomial division:
| convert5 | |
| 9todecimal |
Simplify monomial term number 1
convert5
No simplification is needed
Simplify monomial term number 2
9todecimal
No simplification is needed
Our modified expression is:
| 9todecimal) | |
Check to see if we can simplify constants:
No GCF exists, so we continue,
the constants stay the same in the numerator and denominator.
Simplify a:
We only have a a term in the denominator,
so we leave this where it is
Simplify c:
We have the same c1 term in the numerator and denominator,
so they cancel each other out
Simplify d:
We only have a d term in the denominator,
so we leave this where it is
Simplify e:
We have the same e1 term in the numerator and denominator,
so they cancel each other out
Simplify i:
We only have a i term in the denominator,
so we leave this where it is
Simplify l:
We only have a l term in the denominator,
so we leave this where it is
Simplify m:
We only have a m term in the denominator,
so we leave this where it is
Simplify n:
We only have a n term in the numerator,
so we leave this where it is
Simplify o:
We have the same o1 term in the numerator and denominator,
so they cancel each other out
Simplify r:
We only have a r term in the numerator,
so we leave this where it is
Simplify t:
We only have a t term in the numerator,
so we leave this where it is
Simplify t:
We only have a t term in the denominator,
so we leave this where it is
Simplify t5:
We only have a t5 term in the numerator,
so we leave this where it is
Simplify v:
We only have a v term in the numerator,
so we leave this where it is
Build our final answer:
| convert5 | |
| 9todecimal |
| = |
| nrtt5v |
| 9adilmt |
